Finding bPoint for RPoint and the other way around

RafaŁ Buchner

Is there any less “loopy” way to do these?
(if there is none, then it sucks. it's slowing down my super-duper-fancy unpublished scripts)

def getPointFromBPoint(bPoint):
    """Returns RPoint that is an equivalent to given RBPoint"""
    glyph = bPoint.getParent().getParent() # Normally I use CurrenGlyph()
    onCurvePointsContours = [[p for p in c.points if p.type != "offcurve"] for c in glyph ]
    for i_c,c in enumerate(onCurvePointsContours):
        if bPoint.getParent().index == i_c:
            for i_p,p in enumerate(c):
                if bPoint.index == i_p:
                    return p
                    
def getBPointFromPoint(point):
    """Returns RBPoint that is an equivalent to given RPoint"""
    glyph = point.getParent().getParent() # Normally I use CurrenGlyph()
    onCurvePointsContours = [[p for p in c.points if p.type != "offcurve"] for c in glyph ]
    for i_c,c in enumerate(onCurvePointsContours):
        if point.getParent().index == i_c:
            for i_p,p in enumerate(c):
                if point == p:
                    return glyph[i_c].bPoints[i_p]

Cheers

frederik

from fontParts.fontshell import RBPoint

g = CurrentGlyph()
c = g[0]
p = c.segments[0].onCurve

# point to bPoint
bp = RBPoint()
bp._setPoint(p)
bp.contour = c

print(bp)

# bPoint to point
print(bp._point == p)

RafaŁ Buchner

Thanks!!!!

frederik

from fontParts.fontshell import RBPoint

g = CurrentGlyph()
c = g[0]
p = c.segments[0].onCurve

# point to bPoint
bp = RBPoint()
bp._setPoint(p)
bp.contour = c

print(bp)

# bPoint to point
print(bp._point == p)

gferreira

hello @RafaŁ-Buchner,

you can get a point from a bPoint directly. not sure about the other way around.

def getPointFromBPoint(bPoint):
    return bPoint._point

def getBPointFromPoint(point):
    onCurvePointsContours = [[p for p in c.points if p.type != "offcurve"] for c in point.glyph]
    for ci, c in enumerate(onCurvePointsContours):
        if point.contour.index == ci:
            for pi, p in enumerate(c):
                if point == p:
                    return glyph[ci].bPoints[pi]

# testing
glyph = CurrentGlyph()
bPoint = glyph[0].bPoints[0]
point = getPointFromBPoint(bPoint)
bPoint2 = getBPointFromPoint(point)
print(bPoint)
print(point)
print(bPoint2)
print(bPoint == bPoint2)

note that getParent() is deprecated – you can get parent objects as attributes now: point.contour, point.glyph etc.

good luck!

SOLVED Finding bPoint for RPoint and the other way around